Monday, 20 July 2015

Sql server select list of tables in database

Top sites by search query "sql server select list of tables in database"

  http://www.sommarskog.se/arrays-in-sql-2008.html
(In case you are thinking that XML or delimited strings could be an alternative here, permit me to point out that they, too, represent intermediate storage. One is the push model, where you create a rowset with the metadata, fill the rowset with your data, and in the regular parameter area, you pass the rowset pointer

sql server - How do I get a list of all the partitioned tables in my database? - Database Administrators Stack Exchange


  http://dba.stackexchange.com/questions/14996/how-do-i-get-a-list-of-all-the-partitioned-tables-in-my-database
Note also how this query highlights a flaw on the original question: it is not tables that are partitioned, but indexes (and this includes index 0 and 1, aka

  http://blog.sqlauthority.com/2007/09/16/sql-server-2005-list-all-the-constraint-of-database-find-primary-key-and-foreign-key-constraint-in-database/
Nirmal query gives the table name, but not the column name, because most of the time DEFAULT is created on the column by using DEFAULT, which create the system generated name of the DEFAULT, so I would like to know how to get the column name along with the table name. weeeeeee LOL SQL SERVER 2008 R2 anyway I have to merge 2 databases (finally got it done) one has more columns and tables than the other so I had a heck of a time

  http://blog.sqlauthority.com/2007/06/26/sql-server-2005-list-all-tables-of-database/
ORACLE : STAGE1 : SERVER STAGE2: ONLY 1 DATABASE STAGE3: MORE THAN ONE SCHEMA IN DATABASE If you execute any script at serve level, because there is only one database, it can give you results. Help please as I am trying to set up the connection to the dbase where the user will only be able to see a select set of tables, views and with either userid pass word via ms sql mang console or ODBC have just select access to tables for users, keeping things locked down from the user

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